¿Qué programarías con 4.096 Bytes de Código Fuente?

Fecha de publicación: Jan 07, 2014 1:5:37 AM

Tremendo. Espero que no le cueste el divorcio al programador de ese emulador, pero yo le diría que siguiera adelante a reprogramar toda la historia de la informática. Con esto os daréis cuenta de toda la basura que lleva Windows por dentro. ;-)

http://www.ciencia-explicada.com/2014/01/que-programarias-en-4096-caracteres-de-codigo-en-c.html

Características emuladas:

- CPU Intel 8086/186
- 1MB de RAM
- 8072A 3.5″ floppy disk controller (1.44MB/720KB)
- Contrlador de disco duro (hasta 528MB)
- Tarjeta gráfica Hercules, gráficos 720×348 de 2 colores, 64KB de video RAM y suporte de modo texto CGA 80×25 a 16 colores.
- 8253 programmable interval timer (PIT).
- 8259 programmable interrupt controller (PIC).
- Controlador de teclado 8042, con teclado de 83 teclas tipo XT.
- Reloj de tiempo real MC146818.
- PC speaker.

Código fuente del emulador:

****************************************************************************************************************************************************************

#include "SDL.h" #define $ for(O=9 #define CX M+=(T%3+2*!(!T*t-6)) #define x ,A=4*!T,O=t,W=h=T<3?u(Q?p:D(A+3),D(A),D(A+1)[i]+D(A+2)*g+):K(t),U=V=K(a),o?U=h,W=V:V, #define C 8*-~L #define Z short #define y a(Z)Y[++O] #define B ),a--||( #define _ ),e--||( #define V(I,D,E)(O=a(I)h[r])&&!(A=(D)(V=(1[E+L]<<16)+*i)/O,A-(I)A)?1[E+L]=V-O*(*E=A):H(0) #define i(B,M)B(o){return M;} #define R(O,M,_)(S=L?a(I Z)O:O,N=L?a(I Z)O M(f=a(I Z)_):(O M(f=a(I n)_))) #define T(_)R(r[u(10,L=4,--)],=,_) #define u(a,r,T)16*i[a]+(I Z)(T i[r]) #define a(_)*(_*)& #define L(_)M(W,_,U) #define M(S,F,T)R(r[S],F,r[T]) #define A(_)(i[L=4]+=2,R(_,=,r[u(10,4,-2+)])) #define c(R,T)(1[u=19,L+T]=(N=a(R)h[r]*(R)*T)>>16,*i=N,G(F(N-(R)N))) #define h(_)(1&(L?a(Z)_:_)>>C-1) #define I unsigned #define n char #define e(_)v(F(40[L(_##=40[E]+),E]&N==S|_ N<_(int)S)) I n t,e,l[80186],*E,m,u,L,a,T,o,r[1<<21],X,*Y,b,Q=0,R=0;I Z*i,M,p,q=3;I*localtime(),f,S,kb=0,h,W,U,c,g,d,V,A;N,O,P=983040,j[5];SDL_Surface*k=0;i(K,P+(L?2*o:2*o+o/4&7))i(D,r[a(I)E[259+4*o]+O])i(w,i[o]+=~(-2*47[E])*~L)i(v,(z((f^=S^N)&16),G(N-S&&1&(40[E]^f>>C-1))))J(){V=61442;$;O--;)V+=40[E+O]<<D(25);}i(H,(46[u=76,J(),T(V),T(9[i]),T(M),M(P+18,=,4*o+2),R(M,=,r[4*o]),E]=0))s(o){$;O--;)40[E+O]=1&&1<<D(25)&o;}i(BP,(*i+=262*o*z(F((*E&15)>9|42[E])),*E&=15))i(SP,(w(7),R&&--1[i]&&o?R++,Q&&Q++,M--:0))DX(){$,O*=27840;O--;)O[(I*)k->pixels]=-!!(1<<7-O%8&r[O/2880*90+O%720/8+(88+952[l]/128*4+O/720%4<<13)]);SDL_Flip(k);}main(BX,nE)n**nE;{9[i=E=r+P]=P>>4;$;q;)j[--q]=*++nE?open(*nE,32898):0;read(2[a(I)*i=*j?lseek(*j,0,2)>>9:0,j],E+(M=256),P);$;Y=r+16*9[i]+M,Y-r;Q|R||kb&46[E]&&KB)--64[T=1[O=32[L=(X=*Y&7)&1,o=X/2&1,l]=0,t=(c=y)&7,a=c/8&7,Y]>>6,g=~-T?y:(n)y,d=BX=y,l],!T*t-6&&T-2?T-1?d=g:0:(d=y),Q&&Q--,R&&R--x(O=*Y,O=u=D(51),e=D(8),m=D(14)_ O=*Y/2&7,M+=(n)c*(L^(D(m)[E]|D(22)[E]|D(23)[E]^D(24)[E]))_ L=*Y&8,R(K(X)[r],=,c)_ L=e+=3,o=0,a=X x a=m _ T(X[i])_ A(X[i])_ a<2?M(U,+=1-2*a+,P+24),v(f=1),G(S+1-a==1<<C-1),u=u&4?19:57:a-6?CX+2,a-3||T(9[i]),a&2&&T(M),a&1&&M(P+18,=,U+2),R(M,=,U[r]),u=67:T(h[r])_(W=U B u=m,M-=~L,R(W[r],&,d)B 0 B L(=~)B L(=-),S=0,u=22,F(N>S)B L?c(I Z,i):c(I/**/n,E)B L?c(Z,i):c(n,E)B L?V(I Z,I,i):V(I n,I Z,E)B L?V(Z,int,i):V(n,Z,E))_++e,h=P,d=c,T=3,a=m,M--_++e,13[W=h,i]=(o|=!L)?(n)d:d,U=P+26,M-=~!o,u=17+(m=a)_(a=m B L(+=),F(N<S)B L(|=)B e(+)B e(-)B L(&=)B L(-=),F(N>S)B L(^=)B L(-),F(N>S)B L(=))_!L?L=a+=8 x L(=):!o?Q=1,R(r[p=m x V],=,h):A(h[r])_ T=a=0,t=6,g=c x M(U,=,W)_(A=h(h[r]),V=m?++M,(n)g:o?31&2[E]:1)&&(a<4?V%=a/2+C,R(A,=,h[r]):0,a&1?R(h[r],>>=,V):R(h[r],<<=,V),a>3?u=19:0,a<5?0:F(S>>V-1&1)B R(h[r],+=,A>>C-V),G(h(N)^F(N&1))B A&=(1<<V)-1,R(h[r],+=,A<<C-V),G(h(N*2)^F(h(N)))B R(h[r],+=(40[E]<<V-1)+,A>>1+C-V),G(h(N)^F(A&1<<C-V))B R(h[r],+=(40[E]<<C-V)+,A<<1+C-V),F(A&1<<V-1),G(h(N)^h(N*2))B G(h(N)^F(h(S<<V-1)))B G(h(S))B 0 B V<C||F(A),G(0),R(h[r],+=,A*=~((1<<C)-1>>V)))_(V=!!--1[a=X,i]B V&=!m[E]B V&=m[E]B 0 B V=!++1[i]),M+=V*(n)c _ M+=3-o,L?0:o?9[M=0,i]=BX:T(M),M+=o*L?(n)c:c _ M(U,&,W)_ L=e+=8,W=P,U=K(X)_!R||1[i]?M(m<2?u(8,7,):P,=,m&1?P:u(Q?p:11,6,)),m&1||w(6),m&2||SP(1):0 _!R||1[i]?M(m?P:u(Q?p:11,6,),-,u(8,7,)),43[u=92,E]=!N,F(N>S),m||w(6),SP(!N==b):0 _ o=L,A(M),m&&A(9[i]),m&2?s(A(V)):o||(4[i]+=c)_ R(U[r],=,d)_ 986[l]^=9,R(*E,=,l[m?2[i]:(n)c])_ R(l[m?2[i]:(n)c],=,*E)_ R=2,b=L,Q&&Q++_ W-U?L(^=),M(U,^=,W),L(^=):0 _ T(m[i])_ A(m[i])_ Q=2,p=m,R&&R++_ L=0,O=*E,F(D(m+=3*42[E]+6*40[E])),z(D(1+m)),N=*E=D(m-1)_ N=BP(m-1)_ 1[E]=-h(*E)_ 2[i]=-h(*i)_ 9[T(9[i]),T(M+5),i]=BX,M=c _ J(),T(V)_ s(A(V))_ J(),s((V&~m)+1[E])_ J(),1[E]=V _ L=o=1 x L(=),M(P+m,=,h+2)_++M,H(3)_ M+=2,H(c&m)_++M,m[E]&&H(4)_(c&=m)?1[E]=*E/c,N=*E%=c:H(0)_*i=N=m&E[L=0]+c*1[E]_*E=-m[E]_*E=r[u(Q?p:m,3,*E+)]_ m[E]^=1 _ E[m/2]=m&1 _ R(*E,&,c)_(a=c B write(1,E,1)B time(j+3),memcpy(r+u(8,3,),localtime(j+3),m)),a<2?*E=~lseek(O=4[E][j],a(I)5[i]<<9,0)?(a?write:read)(O,r+u(8,3,),*i):0:0),O=u,D(16)?v(0):D(17)&&G(F(0)),CX*D(20)+D(18)-D(19)*~!!L,D(15)?O=m=N,41[43[44[E]=h(N),E]=!N,E]=D(50):0,!++q?kb=1,*l?SDL_PumpEvents(),k=k?k:SDL_SetVideoMode(720,348,32,0),DX():k?SDL_Quit(),k=0:0:0;}i(F,40[E]=!!o)i(z,42[E]=!!o)i(G,48[E]=o)

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